<Integration by parts>
Solve ∫ t sin t dt.
We can easily solve it with tabular integration.
[derived] [interated]
t sin t
1 -cos t
0 -sin t
Point:
1. Functions derived to make them simple to the left
2. Functions integrated to make them simple to the right
Then pairing t and -cos t, 1 and -sin t, and 0 and -sin t,
and multiplying each, we get
-t cos t, -sin t, and 0,
Multiplying +1 and -1 in this order by each.
This results in
∫ t sint dt = -t cos t + sin t + C, where C is a constant number.
<Example>
∫x^3 exp(x^2)dx = ∫x^2 exp(x^2) (xdx) = ∫x^2 exp(x^2) (1/2dx^2)
Let t = x^2,
[derived] [interated]
t exp(t)
1 exp(t)
0 exp(t)
∫t exp(t) (1/2dt) = 1/2 {t exp(t) - exp(t)} + C
Therefore
∫x^3 exp(x^2)dx = 1/2 {x^2 exp(x^2) - exp(x^2)} + C
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