03. December 2016 (1/3)^x < 2 Real solution: (1/3)^x < 2 log{(1/3)^x} < log(2) where log(x) is the natural logarithm. x log(1/3) < log(2) Noting that log(1/3) is negative. x > log(2)/log(1/3) tagPlaceholderTags: math Write a comment Comments: 0
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