∛3∛5 = ∛(3*5)

e.g.

√3√5 = √(3*5)

√3/√5 = √(3/5)

If 0 < 1 < 2, then

2^0 < 2^1 < 2^2,

(1/2)^0 > (1/2)^1 > (1/2)^2.

If 1 < 2 < 3, then

log2 1 < log2 2 < log2 3,

log1/2 1 > log1/2 2 > log1/2 3.